A father is twice as old as his son. 20 years ago the age of the father

was 12 times the age of the son. The present age of the father is :
 a) 40 yrs
 b) 28 yrs
 c) 32 yrs
 d) 44 yrs

Bevco AsstGrII-15

44 yrs

Solution

Let present  age of  son = a
Then age of father = 2a

20 years ago, age of son= (a-20)
20 years ago, age of father= (2a-20)

2a-20 = 12(a-20)
2a - 20 = 12a - 240
10a = 220

a=22
Age of father= 2x22 =44

Answer